5/2x^2=640

Solution for 5/2x^2=640 equation:

5/2x^2=640

We move all terms to the left:

5/2x^2-(640)=0


Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-640*2x^2+5=0

Wy multiply elements

-1280x^2+5=0

a = -1280; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-1280)·5
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*-1280}=\frac{-160}{-2560}
=1/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*-1280}=\frac{160}{-2560}
=-1/16
$